Thursday, June 05, 2008
Commandment VII
I am about half way through illustrating Commandment VII, "You shall not commit adultery." In preparation for this illustration, I decided to calculate how many different combinations of adultery there are, assuming one member of a couple cheats with one other adult. My findings are neatly summarized in this Excel table.
Note: I couldn't remember how to calculate this with factorials. If anyone knows the equation for this, please elucidate.
I am about half way through illustrating Commandment VII, "You shall not commit adultery." In preparation for this illustration, I decided to calculate how many different combinations of adultery there are, assuming one member of a couple cheats with one other adult. My findings are neatly summarized in this Excel table.
Note: I couldn't remember how to calculate this with factorials. If anyone knows the equation for this, please elucidate.
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How many combinations can you add with the family Pet (a la Sleeping Dogs Lie).
http://www.imdb.com/title/tt0492492/
http://www.imdb.com/title/tt0492492/
Um, thanks Bob, good question. Does anyone seriously know how to calculate this with the factorial equation? It bothers me that I can't remember.
To figure out a factorial (n!), you must multiply all the integers from 1 to n.
Example: 3! = 3x2x1=6
In this case I believe you have 4! Which gives you 24.
Example: 3! = 3x2x1=6
In this case I believe you have 4! Which gives you 24.
Thanks. I think you're right about the 4 slots, but 24 sounds too high. Maybe it's like this:
Person # 1 in couple = man or woman, 2!
Person # 2 in couple = man or woman, 2!
Cheater = man or woman, 2!
Cheats with = man or woman, 2!
This would be 2! + 2! + 2! + 2!, or 8 total. Does this sound right to anyone? Lisa, please help.
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Person # 1 in couple = man or woman, 2!
Person # 2 in couple = man or woman, 2!
Cheater = man or woman, 2!
Cheats with = man or woman, 2!
This would be 2! + 2! + 2! + 2!, or 8 total. Does this sound right to anyone? Lisa, please help.
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